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![[tex]1x10^{19}m^{-3}[/tex]](images/latex/c3a697b918e490688a9098d37e2f48991e3672ae_0.png "[tex]1x10^{19}m^{-3}[/tex]")
. A) Hallar la energía del nivel donor y la
![[tex]E_{g}=1.12eV, N_{c}=2.8x10^{25} m^{-3} , N_{v}= 1.04x10^{25} m^{-3}, n_{i}=6.68x10^{15} m^{-3},\\ E_{i}=0,045 eV, \mu_{n}=0,1600 m^{2}.V^{-1}.s^{-1} y\mu_{p}=0,043 m^{2}.V^{-1}.s^{-1}[/tex]](images/latex/b93a16c5bb2eb0613bf049f1a71342531ac4b70d_0.png "[tex]E_{g}=1.12eV, N_{c}=2.8x10^{25} m^{-3} , N_{v}= 1.04x10^{25} m^{-3}, n_{i}=6.68x10^{15} m^{-3},\\ E_{i}=0,045 eV, \mu_{n}=0,1600 m^{2}.V^{-1}.s^{-1} y\mu_{p}=0,043 m^{2}.V^{-1}.s^{-1}[/tex]")
![[tex]n + N^{-}_{a} = p + N^{+}_{d}[/tex]](images/latex/c2f7724d25e6bf78af5804c90764728be0430346_0.png "[tex]n + N^{-}_{a} = p + N^{+}_{d}[/tex]")
![[tex]n + N^{-}_{a} = n + 0 = p + N^{+}_{d} = p + N_{d} [/tex]](images/latex/bef2f1147e1b87817fcde777f431997c6ce84e6b_0.png "[tex]n + N^{-}_{a} = n + 0 = p + N^{+}_{d} = p + N_{d} [/tex]")
![[tex]n = p + N_{d} [/tex]](images/latex/ff4ded92836cbe607a152da0278d1ca69abfb54e_0.png "[tex]n = p + N_{d} [/tex]")
![[tex]n = \frac{1}{2}N_{d} + \sqrt{\frac{1}{4}N_{d}^{2} + n_{i}^{2}} = 1.0000004x10^{19} m^{-3}[/tex]](images/latex/e05445dcb7b43493a835e5fbd00770ab873c4b1a_0.png "[tex]n = \frac{1}{2}N_{d} + \sqrt{\frac{1}{4}N_{d}^{2} + n_{i}^{2}} = 1.0000004x10^{19} m^{-3}[/tex]")
![[tex]n = N_{c}e^{\frac{-(E_{g} - E_{f})}{kT}}[/tex]](images/latex/ce9cbe561c79bdacfa59a09872d187a373b45550_0.png "[tex]n = N_{c}e^{\frac{-(E_{g} - E_{f})}{kT}}[/tex]")
![[tex]E_{f} = E_{g} + kTln{\frac{n}{N_{c}}} = 0.737eV[/tex]](images/latex/120651923974fcb8a81396ab5a40afdf9324f096_0.png "[tex]E_{f} = E_{g} + kTln{\frac{n}{N_{c}}} = 0.737eV[/tex]")
![[tex]E_{g} - E_{d} = E_{i}[/tex]](images/latex/1f1bcba2f0a82ad27f537505e18bb1e0a5578a07_0.png "[tex]E_{g} - E_{d} = E_{i}[/tex]")
![[tex]E_{g} - E_{i} = E_{d} = 1.12eV - 0.045eV = 1.075eV[/tex]](images/latex/fab80161ef9f82e7fc60ce46ba78a08f0f94becf_0.png "[tex]E_{g} - E_{i} = E_{d} = 1.12eV - 0.045eV = 1.075eV[/tex]")
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