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![[tex]1 - p = P(99 \le D \le 101)[/tex]](images/latex/4d9883534884e4f46b4a51dd3e344d2ab5b2237c_0.png "[tex]1 - p = P(99 \le D \le 101)[/tex]")
![[tex]Z = \frac{D -100}{\sigma}[/tex]](images/latex/05bbebb7888bdb7c81b33d54d14700548785eeae_0.png "[tex]Z = \frac{D -100}{\sigma}[/tex]")
tiene distribución ![[tex]N(0,1)[/tex]](images/latex/f52812b88013dc29b27d33c3b8204bab57f8876d_0.png "[tex]N(0,1)[/tex]")
![[tex]1 - p = P(99 \le D \le 101) = P(-\frac{1}{\sigma} \le Z \le \frac{1}{\sigma}) = 2\Phi(\frac{1}{\sigma}) - 1[/tex]](images/latex/40f3b92ce6f40c88506fecb7e886ff9f37d37750_0.png "[tex]1 - p = P(99 \le D \le 101) = P(-\frac{1}{\sigma} \le Z \le \frac{1}{\sigma}) = 2\Phi(\frac{1}{\sigma}) - 1[/tex]")
![[tex]\sigma^2[/tex]](images/latex/0bf6b5ab83fe2e8540595f387ce935df88539782_0.png "[tex]\sigma^2[/tex]")
![[tex]\sigma^2 = \frac{1}{(\Phi^{-1}(1-\frac{p}{2}))^2}[/tex]](images/latex/41e2fcaf2f55a9d549cd5185948e99d56952c049_0.png "[tex]\sigma^2 = \frac{1}{(\Phi^{-1}(1-\frac{p}{2}))^2}[/tex]")
![[tex]\widehat{\sigma^2_{MV}} = \frac{1}{(\Phi^{-1}(1-\frac{\widehat{p}_{MV}}{2}))^2}[/tex]](images/latex/cf0578346c7f1503c3bc87361a1c9e88b263f061_0.png "[tex]\widehat{\sigma^2_{MV}} = \frac{1}{(\Phi^{-1}(1-\frac{\widehat{p}_{MV}}{2}))^2}[/tex]")
![[tex]\widehat{p_{MV}} = 0.2[/tex]](images/latex/a39ed5c7718e3e5191dc7499e89d4d789fd7014d_0.png "[tex]\widehat{p_{MV}} = 0.2[/tex]")
en este problema.
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